GT's Blog

Check if a class extends another at Runtime : Java

Summary :

If you want to know whether or not a Class extends another, use Class#isAssignableFrom(Class)
Class#isAssignableFrom(Class) also returns true if both classes are same
To find if an object is instance of a class use instanceof operator
To know if a class is direct sub class of another class then use Class#getSuperClass().equals(Class)

Setup :

We have an interface MyInterface and three classes MyBaseClass, MySubClass and SomeOtherClass with the below hierarchy.

interface MyInterface {
}

class MyBaseClass implements MyInterface {
}

class MySubClass extends MyBaseClass {
}

class SomeOtherClass {
}

Tests:

   

public class Test {
  
  public static void main( String[] args ) {
    
    /*
     * Checking if a class is same as or is a superclass or superinterface
     * 
     * of another class (the class in parameter)
     */
    System.out.println( MyBaseClass.class.isAssignableFrom( MyBaseClass.class ) );// true : same class
    System.out.println( MyBaseClass.class.equals( MyBaseClass.class ) );// true : same class
    System.out.println( MyBaseClass.class.isAssignableFrom( MySubClass.class ) );// true : superclass
    System.out.println( MyInterface.class.isAssignableFrom( MySubClass.class ) );// true : superinterface
    System.out.println( MyBaseClass.class.isAssignableFrom( SomeOtherClass.class ) );// false : the two classes has no relation
    System.out.println( MySubClass.class.isAssignableFrom( MyBaseClass.class ) );// false : MySubClass is not the superclass
    
    /*
     * Checking if a object is instance of a class
     */
    
    IMyInterface object = new MyBaseClass( );
    System.out.println( object instanceof MyInterface ); // true
    System.out.println( object instanceof MyBaseClass ); // true
    System.out.println( object instanceof MySubClass ); // false
    System.out.println( object instanceof SomeOtherClass );// false
    
    /*
     * check if a class is direct superclass of another
     */
    
    System.out.println( MySubClass.class.getSuperclass( ).equals( MyInterface.class ) );// false : its not a directsuper class, interface
    System.out.println( MyBaseClass.class.getSuperclass( ).equals( MyInterface.class ) );// false : its not a directsuper class, interface
    System.out.println( MySubClass.class.getSuperclass( ).equals( MyBaseClass.class ) );// true : MyBaseClass is extending MySubClass
  }
}

Full code :

   

public class Test {
  
  public static void main( String[] args ) {
    
    /*
     * Checking if a class is same as or is a superclass or superinterface
     * 
     * of another class (the class in parameter)
     */
    System.out.println( MyBaseClass.class.isAssignableFrom( MyBaseClass.class ) );// true : same class
    System.out.println( MyBaseClass.class.equals( MyBaseClass.class ) );// true : same class
    System.out.println( MyBaseClass.class.isAssignableFrom( MySubClass.class ) );// true : superclass
    System.out.println( MyInterface.class.isAssignableFrom( MySubClass.class ) );// true : superinterface
    System.out.println( MyBaseClass.class.isAssignableFrom( SomeOtherClass.class ) );// false : the two classes has no relation
    System.out.println( MySubClass.class.isAssignableFrom( MyBaseClass.class ) );// false : MySubClass is not the superclass
    
    /*
     * Checking if a object is instance of a class
     */
    
    IMyInterface object = new MyBaseClass( );
    System.out.println( object instanceof MyInterface ); // true
    System.out.println( object instanceof MyBaseClass ); // true
    System.out.println( object instanceof MySubClass ); // false
    System.out.println( object instanceof SomeOtherClass );// false
    
    /*
     * check if a class is direct superclass of another
     */
    
    System.out.println( MySubClass.class.getSuperclass( ).equals( MyInterface.class ) );// false : its not a directsuper class, interface
    System.out.println( MyBaseClass.class.getSuperclass( ).equals( MyInterface.class ) );// false : its not a directsuper class, interface
    System.out.println( MySubClass.class.getSuperclass( ).equals( MyBaseClass.class ) );// true : MyBaseClass is extending MySubClass
  }
}

interface MyInterface {
}

class MyBaseClass implements MyInterface {
}

class MySubClass extends MyBaseClass {
}

class SomeOtherClass {
}

superclass "javax.servlet.http.HttpServlet" not found on Java Build Path - solution

You might (normally) get the error following error on a dynamic java web project created through maven on Eclipse IDE. The solution is simple :
Error :

The superclass "javax.servlet.http.HttpServlet" was not found on the Java Build Path

Error Location :

<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>

Solution 1)
Edit pom.xml to include servlet-api-x.x.jar in your dependencies:

<dependency>
  <groupId>javax.servlet</groupId>
  <artifactId>javax.servlet-api</artifactId>
  <version>3.1.1</version>
  <scope>provided</scope>
</dependency>

Solution 2)
Go to Project->Properties->Target Runtimes . And add your server container eg. : Apache Tomcat

Java Obsfucate Password - Replace with asterisk

Obsfucate password :

Rreplace everything except first and last character by asterisk ( * ), if the password is less than ALLOWED_LENGTH characters long obfuscate it entirely i.e., prints asterisks

Code :

   
//Test 
System.out.println( getObfuscatedPassword( "" ) ); //returns null
System.out.println( getObfuscatedPassword( "pwdd" ) ); //returns ****
System.out.println( getObfuscatedPassword( "mySecurePassword" ) ); // returns m**************d


//Method 
public static String getObfuscatedPassword( String password ) {
   
   int ALLOWED_LENGTH = 5;
   
   if ( null == password || "".equals( password.trim( ) ) ) {
    return null;
   }
   
   StringBuilder builder = new StringBuilder( );
   
   if ( password.length( ) < ALLOWED_LENGTH ) {
   
    for ( int i = password.length( ); i != 0; i-- ) {
     builder.append( "*" );
    }
   
    return builder.toString( );
   }
   
   builder.append( password.charAt( 0 ) );
   
   for ( int i = password.length( ) - 2; i != 0; i-- ) {
    builder.append( "*" );
   }
   
   return builder.append( password.substring( password.length( ) - 1 ) ).toString( );
}

change maven local repository path - symbolic links

Let's suppose we want to change the local maven repo path (default : c:\users\user_name\.m2\repository) to some other real folder - lets say e:\repo - so that the contents from e:\repo folder are mapped to the default folder location.

This might be useful when .m2 folder on your C: drive is taking too much space. In such case, you can move the content to another drive ( e:\repo) and have a symbolic link on C:\ drive instead - so that all the configuration remains intact.

The following command creates a link folder "repository" in /.m2 folder and points to the source e:\REPO

C:\>mklink /d c:\users\gtiwari\.m2\repository e:\REPO

Note:

Syntax : mklink /d TARGET SOURCE_DIR
For more information about the mklink command visit : http://ganeshtiwaridotcomdotnp.blogspot.com/2014/08/using-symbolic-links-on-windows.html
we can do it using other options as mentioned in http://stackoverflow.com/questions/71030/can-i-add-maven-repositories-in-the-command-line

using symbolic links on windows

Using symbolic links (MKLINK comand) on windows:

Suppose we want to create a link of folder 'e:\source' to c:\target\bridge then, use the following command:

C:\>mklink /d c:\target\bridge e:\source

Syntax : mklink /d TARGET SOURCE_DIR

This command creates a link folder "bridge" in c:\target\ where you can see the contents from e:\source.

For more info :

Visit: http://ss64.com/nt/mklink.html -